C Number pattern 1 program using For loop

Write "C"  program to print below Number pattern 1:


To understand this example, you should have the knowledge of the following topics:

·                     C if Else Statement
·                      C For loop
·                     C programming operators

C Number pattern program using For loop:
#include <stdio.h>
int main()
{
    int i, j;
    for(i = 5; i >= 1; i--)
    {
        for(j = 1; j <= i ;j++)
        {
            printf("%d",j);
        }
        printf("\n");
    }
    return 0;

}
Output:
12345
1234
123
12
1
Explanation:
  • First two integers "i" and "j" are declared of type int.
  • Then in the First for loop “i” value is initialized with value 5.
  • Now “i” value is checked with the condition i >= 1 that is (5 >=1). So the condition is True.
  • Now the loop enters into second for loop and checks the condition j <= i.
  • So the value of j=1 is less than “i” where (i =5) the condition is true. So it's print the value of “J”. And the value of “j” increments after printing value. It prints the value of J up to “j = 5” when becomes 6 it comes out the loop and increment value i = 2 and same process repeats.
  • Last where “i” value becomes “0” the first for loop condition becomes false and the program terminates.
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