C Number pattern 15 program using For loop

Write "C"  program to print below Number pattern 15:

To understand this example, you should have knowledge of the following topics:
·     C if Else Statement
·     C For loop
·      C programming operators
C Number pattern 15 program using For loop:
#include <stdio.h> int main() { int i, j; for(i=1;i<=4;i++) { for(j=i;j>=1;j--) { printf("%d",j%2); } printf("\n"); } return 0; }
Output:
1
01
101
0101
Explanation:
  • First two integers "i", and "j" are declared of type int.
  • Then in the First for loop “i” value is initialized with a value 1.
  • Now “i” value is checked with the condition i <= 4 that is (1 <= 4). So the condition is True.
  • Now the loop enters into second for loop and checks the condition j >= 1. Where "j = 1". and print the value of "j%2".
  • The value of "j" prints up to condition becomes False.
  • Now the value of "i" will be incremented by the condition "i = i++" and executes the loop.
  • when the value of "i"  becomes "5" the program terminates.
See also: 
Share:

Our Services

Search This Blog

  • ()
Powered by Blogger.

TikTok Sign Up and Account Registration in detail

TikTok Sign Up and Account Registration  The steps to create an account on Tik Tok application for Android and ios. Download and introd...

Blog Archive