C Number pattern 15 program using For loop

Write "C"  program to print below Number pattern 15:

To understand this example, you should have knowledge of the following topics:
·     C if Else Statement
·     C For loop
·      C programming operators
C Number pattern 15 program using For loop:
#include <stdio.h> int main() { int i, j; for(i=1;i<=4;i++) { for(j=i;j>=1;j--) { printf("%d",j%2); } printf("\n"); } return 0; }
Output:
1
01
101
0101
Explanation:
  • First two integers "i", and "j" are declared of type int.
  • Then in the First for loop “i” value is initialized with a value 1.
  • Now “i” value is checked with the condition i <= 4 that is (1 <= 4). So the condition is True.
  • Now the loop enters into second for loop and checks the condition j >= 1. Where "j = 1". and print the value of "j%2".
  • The value of "j" prints up to condition becomes False.
  • Now the value of "i" will be incremented by the condition "i = i++" and executes the loop.
  • when the value of "i"  becomes "5" the program terminates.
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