C Number pattern 16 program using For loop

Write "C"  program to print below Number pattern 16:

To understand this example, you should have knowledge of the following topics:
·     C if Else Statement
·     C For loop
·      C programming operators
C Number pattern 16 program using For loop:
#include <stdio.h> int main() { int i,j; for(i=1;i<=9;i+=2) { for(j=i;j<=9;j+=2) { printf("%d",j); } printf("\n"); } return 0; }
Output:
13579
3579
579
79
9
Explanation:
  • First two integers "i", and "j" are declared of type int.
  • Then in the First for loop “i” value is initialized with a value 9.
  • Now “i” value is checked with the condition i <= 9 that is (1 <= 9). So the condition is True.
  • Now the loop enters into second for loop and checks the condition j <= 9. Where "j = 1". and the condition is True print the value of "j".
  • The value of "j" prints up to condition becomes False.
  • Now the value of "i" will be incremented by the condition "i = i+2" and executes the loop.
  • when the value of "i"  becomes "11" the program terminates.
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