C Number pattern 17 program using For loop

Write "C"  program to print below Number pattern 17:

To understand this example, you should have knowledge of the following topics:
·     C if Else Statement
·     C For loop
·      C programming operators
C Number pattern 17 program using For loop:
#include<stdio.h> int main() { int i,j,k; for(i=1;i<=5;i++) { if(i%2==0) { k=2; } else { k=1; } for(j=1;j<=i;j++,k+=2) { printf("%d ", k); } printf("\n"); } return 0; }
Output:
1
24
135
2468
13579
Explanation:
  • First two integers "i", and "j" are declared of type int.
  • Then in the First for loop “i” value is initialized with a value 5.
  • Now “i” value is checked with the condition i <= 5 that is (1 <= 5). So the condition is True.
  • Now Loop check if condition "i % 2" if the condition is True k value becomes "2" if the condition is false K value becomes "1"
  • Now the loop enters into second for loop and checks the condition j <= i. Where "j = 1". and the condition is True print the value of "k".
  • The value of "j" prints up to condition becomes False.
  • Now the value of "i" will be incremented by the condition "i = i++" and executes the loop.
  • when the value of "i"  becomes "6" the program terminates.
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