C Number pattern 18 program using For loop

Write "C"  program to print below Number pattern 18:

To understand this example, you should have knowledge of the following topics:
·     C if Else Statement
·     C For loop
·      C programming operators
C Number pattern 18 program using For loop:
#include<stdio.h> int main() { int i, j, k; for(i=5;i>=1;i--) { k = i; for(j=1;j<=5;j++) { if(k <= 5) { printf("%d",k); } else { printf("5"); } k++; } printf("\n"); } return 0; }
Output:
55555
45555
34555
23455
12345
Explanation:
  • First three integers "i", "j" and "k" are declared of type int.
  • Then in the First for loop “i” value is initialized with a value 5.
  • Now “i” value is checked with the condition i >= 1 that is (5 >= 1). So the condition is True.
  • Now the loop enters into second for loop and checks the condition j <= 5. Where "j = 1". and the condition is True.
  • Now Loop checks if condition "k <=5"  where "k = 5" if the condition is True prints the k value if the Condition is False prints "5". Print up to second for loop condition becomes False.
  • when the value of "i"  becomes "0" the program terminates.
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