C Number pattern 19 program using For loop

Write "C"  program to print below Number pattern 19:

To understand this example, you should have knowledge of the following topics:
·     C if Else Statement
·     C For loop
·      C programming operators
C Number pattern 19 program using For loop:
#include<stdio.h> int main() { int i,j,k; k=1; for(i=1;i<5;i++) { for(j=1;j<=i;j++) { printf("%d",k++); } printf("\n"); } return 0; }
Output:
1
23
456
78910
Explanation:
  • First three integers "i", "j" and "k" are declared of type int.
  • Then in the First for loop “i” value is initialized with a value 1.
  • Now “i” value is checked with the condition i < 5 that is (1 < 5). So the condition is True.
  • Now the loop enters into second for loop and checks the condition j <= i. Where "j = 1". and the condition is True.
  • Now prints the k value by condition "k++". Print up to second for loop condition becomes False.
  • when the value of "i"  becomes "6" the program terminates.
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