Write "C"  program to print below Number pattern 3:

To understand this example, you should have knowledge of the following topics:
·      C programming operators

C Number pattern 3 program using For loop:
#include <stdio.h>
int main()
{
int i, j;
for(i = 5;  i >= 1;i--)
{
for(j = i; j >= 1; j--)
{
printf("%d",j);
}
printf("\n");
}
return 0;

}
Output:
`54321`
`4321`
`321`
`21`
`1`
Explanation:
• First two integers "i" and "j" are declared of type int.
• Then in the First for loop “i” value is initialized with value 5.
• Now “i” value is checked with the condition i >= 1 that is (5 >=1). So the condition is True.
• Now the loop enters into second for loop and checks the condition j >= i.
• So the value of j=5 is greater than “1” where (j =5) the condition is true. So it's print the value of “J”. And the value of “j” decrements after printing value. It prints the value of J up to “j = 1” when becomes 0 it comes out the loop and increment value i = 4 and the same process repeats.
• Last where “i” value becomes “0” the first for loop condition becomes false and the program terminates.

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