## Write "C"  program to print below Number pattern 4:

To understand this example, you should have knowledge of the following topics:
·      C programming operators

C Number pattern 4 program using For loop:
#include <stdio.h>
int main()
{
int i, j;
for(i =1;i<=5;i++)
{
for(j=5;j>=i;j--)
{
printf("%d",j);
}
printf("\n");
}
return 0;
}
Output:
```54321
5432
543
54
5
```
Explanation:
• First two integers "i" and "j" are declared of type int.
• Then in the First for loop “i” value is initialized with a value 1.
• Now “i” value is checked with the condition i <= 5 that is (1<>= 5). So the condition is True.
• Now the loop enters into second for loop and checks the condition j >= i.
• So the value of j=5 is greater than “1” where (j =5) the condition is true. So it's print the value of “J”. And the value of “j” decrements after printing value. It prints the value of J up to “j = 1” when becomes 0 it comes out the loop and increment value i = 2 and the same process repeats.
• Last where “i” value becomes “6” the first for loop condition becomes false and the program terminates.