C Number pattern 4 program using For loop

Write "C"  program to print below Number pattern 4:




To understand this example, you should have knowledge of the following topics:
·     C if Else Statement
·     C For loop
·      C programming operators

C Number pattern 4 program using For loop:
#include <stdio.h>
int main()
{
    int i, j;
    for(i =1;i<=5;i++)
    {
        for(j=5;j>=i;j--)
        {
            printf("%d",j);
        }
        printf("\n");
    }
    return 0;
}
Output:
54321
5432
543
54
5
Explanation:
  • First two integers "i" and "j" are declared of type int.
  • Then in the First for loop “i” value is initialized with a value 1.
  • Now “i” value is checked with the condition i <= 5 that is (1<>= 5). So the condition is True.
  • Now the loop enters into second for loop and checks the condition j >= i.
  • So the value of j=5 is greater than “1” where (j =5) the condition is true. So it's print the value of “J”. And the value of “j” decrements after printing value. It prints the value of J up to “j = 1” when becomes 0 it comes out the loop and increment value i = 2 and the same process repeats.
  • Last where “i” value becomes “6” the first for loop condition becomes false and the program terminates.
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