## Write "C"  program to print below Number pattern 6:

To understand this example, you should have knowledge of the following topics:
·      C programming operators

C Number pattern 6 program using For loop:
```#include <stdio.h>
int main()
{
int i, j;
for(i=5;i>=1;i--)
{
for(j=i;j<=5;j++)
{
printf("%d",j);
}
printf("\n");
}
return 0;
}
```
Output:
```5
45
345
2345
12345

```
Explanation:
• First two integers "i" and "j" are declared of type int.
• Then in the First for loop “i” value is initialized with a value 5.
• Now “i” value is checked with the condition i >= 1 that is (5 >= 1). So the condition is True.
• Now the loop enters into second for loop and checks the condition j <= 5. Where "j = 5".
• So the value of j=5 is equal to the value of "i" it prints the value if "j". Now the value of "j" is incremented to "6" the second for loop condition becomes false loop come out from the for loop.
• Now the value of "i" is decremented to "4" and repeat the same process.
• Last where “i” value becomes “0” the first for loop condition becomes false and the program terminates.