## Write "C"  Program to print below Alphabet Pattern21 (or) Character Pattern21:

To understand this example, you should have knowledge of the following topics:
·     C programming operators
C Character pattern21 program using For loop:
```
#include<stdio.h>
void main()
{
int i,j,k;
printf("Enter the number of lines\n");
scanf("%d",&k);
for(i = 1;i <= k;i++)
{```
```         for(j = 1;j <= k-i;j++)
{```
`           printf(" ");`
`        }`
```         for(j = 1;j <= i;j++)
{
printf("%c",(char)(j+64));```
`          }`
`          for(j = i-1; j >= 1; j--)`
`         {`
`           printf("%c",(char)(j+64));`
`         }`
`          printf("\n");`
`        }`
```   }
```

Output:
```
Enter the number of lines
5
A
ABA
ABCBA
ABCDCBA
ABCDEDCBA
```
Explanation:
• First three integers "i", "j", "k" are declared of type int.
• Then in the First for loop “i” value is initialized with a value of "1".
• Now “i” value is checked with the condition "i <= k" (where "k" value is given through Keyboard). If the condition is True loops enter into second for loop.
• Now the loop enters into second for loop and checks the condition "j <= k-i". Where "j = 1". and the condition is True prints the statement.
• Now the loop enters into third for loop and checks the condition "j <= i". If the condition is True prints the statement.
• Now the loop enters into fourth for loop and checks the condition "j >= 1". If the condition is True prints the statement.
• Now prints the " Alphabet". Print up to third for loop condition becomes False.
• When the value of "k"  becomes less than "i" value the program terminates.

• ()