Java Number pattern 18 program using For loop

Write "Java"  program to print below Number Pattern 18:

To understand this example, you should have knowledge of the following topics:

·  Java For loop
·   Java programming operators.

Java Number pattern 18 program using For loop:
class numberPattern18
{
public static void main(String[] ags)
{
    int i, j, k;
  for(i=5;i>=1;i--)
  {
    k = i;
    for(j=1;j<=5;j++)
    {
      if(k <= 5)
      {
        System.out.print(k);
      }
      else
      {
        System.out.print("5");
      }
      k++;
    }
    System.out.println();
  }
 }
}
}
Output:
55555
45555
34555
23455
12345
Explanation:


  • First three integers "i", "j" and "k" are declared of type int.
  • Then in the First for loop “i” value is initialized with a value 5.
  • Now “i” value is checked with the condition i >= 1 that is (5 >= 1). So the condition is True.
  • Now the loop enters into second for loop and checks the condition j <= 5. Where "j = 1". and the condition is True.
  • Now Loop checks if condition "k <=5"  where "k = 5" if the condition is True prints the k value if the Condition is False prints "5". Print up to second for loop condition becomes False.
  • when the value of "i"  becomes "0" the program terminates.
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