Java Number pattern 19 program using For loop

Write "Java"  program to print below Number Pattern 19:

To understand this example, you should have knowledge of the following topics:

·  Java For loop
·   Java programming operators.

Java Number pattern 19 program using For loop:
class numberPattern19
{
public static void main(String[] ags)
{
   int i,j,k;
  k=1;
  for(i=1;i<5;i++)
  {
    for(j=1;j<=i;j++)
    {
      System.out.print(k++);
    }
    System.out.println();
   }
 }
}
Output:
1
23
456
78910
Explanation:

  • First three integers "i", "j" and "k" are declared of type int.
  • Then in the First for loop “i” value is initialized with a value 1.
  • Now “i” value is checked with the condition i < 5 that is (1 < 5). So the condition is True.
  • Now the loop enters into second for loop and checks the condition j <= i. Where "j = 1". and the condition is True.
  • Now prints the k value by condition "k++". Print up to second for loop condition becomes False.
  • when the value of "i"  becomes "6" the program terminates.
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