Alphabet Pattern (or) Character Pattern21 Program in Java

Write "Java"  Program to print below Alphabet Pattern21 (or) Character Pattern21:

To understand this example, you should have knowledge of the following topics:

·  Java For loop
·   Java programming operators.

Java Character pattern 21 program using For loop:
import java.util.Scanner;
class alphabetPattern21
{
public static void main(String[] ags)
{
    int i, j,k;
   System.out.println("Enter the number of lines");
   Scanner s = new Scanner(System.in);
   k = s.nextInt();
    for(i = 1;i <= k;i++)
    {  
        for(j = 1;j <= k-i;j++)
           {
            System.out.print(" ");
            }
           for( j = 1; j <= i; j++)
           {
            System.out.print((char)(j+64));
            }
          for( j = i -1; j >= 1; j--)
           {
            System.out.print((char)(j+64));
           }
        System.out.println();
    }
  }
}
Output:
Enter the number of lines 5
A
ABA
ABCBA
ABCDCBA
ABCDEDCBA
Explanation:
  • First three integers "i", "j", "k" are declared of type int.
  • Then in the First for loop “i” value is initialized with a value of "1". 
  • Now “i” value is checked with the condition "i <= k" (where "k" value is given through Keyboard). If the condition is True loops enter into second for loop.
  • Now the loop enters into second for loop and checks the condition "j <= k-i". Where "j = 1". and the condition is True prints the statement.
  • Now the loop enters into third for loop and checks the condition "j <= i". If the condition is True prints the statement.
  • Now the loop enters into fourth for loop and checks the condition "j >= 1". If the condition is True prints the statement.
  • Now prints the " Alphabet". Print up to third for loop condition becomes False.
  • When the value of "k"  becomes less than "i" value the program terminates.
See also: 
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